Airlift Pump Challenge
What is an Airlift Pump? How does it work?
An airlift pump is a device that is made used
of compressed air to lift water from a well or sump. As we know, the density of
water is significantly greater than the density of air. Hence, when compressed
air is combined with water in an airlift pump, air that has a lower density than
water will rise due to buoyancy. In the meantime, the water is taken in the
ascendant airflow and flows in the same direction as the air. Air is fed into
the bottom of the riser pump and this air combines with water and form froth. Hence,
the air and water mixture which is also called froth has a much lower density than
water. Due to the different densities, the water mixture is able to flow out. In
conclusion, the main principle of an airlift pump applied is density difference.
Experimentation
|
Members |
Role |
Responsibilities |
|
Zelene |
Team Leader |
·
Ensured that all the runs for the experiments were
done ·
Helped to keep track of the run that was being
done |
|
Zhi Wei |
Recorder |
Wrote down the data collected during the experiment and helped to
calculate the flowrate from the volume measured |
|
Uzair |
Timekeeper |
Helped Experimenter to keep track of time to record the volume of
water that was being transferred by the pump |
|
Rydrew |
Experimenter |
Worked with the given materials to conduct the experiment, does
the data collection and experiment setup |
- A small air pump (Super Y Classica ^_^)
- A 99 cm piece of flexible tubing
- 5 small tube connectors
- A green U-tube
- A small metal ball valve
- Super Glue
- A wooden chopstick
- A large plastic container
- A tall cylindrical container (28.5 cm height)
In the photo above, there is a lot of residual super glue that can be seen from the numerous attempts that took to attach the flexible tube to the U-tube. Rydrew made the mistake of buying adjustable super glue instead of a quick-setting one >.< To aid with the setting process, a chopstick was used to keep the tube in place.
After a few hours of waiting (and one night to let the glue fully set), the pump setup was complete!
The New Challenge
The distance between the water level and the opening of the flexible tubing was also measured, as X for Experiment 1 and Y for Experiment 2.
The Container Problem
And that wraps up the experimentation part of the Air Lift Pump Challenge!
Practical Report
1.
Plot
tube length X versus pump flowrate. (X is the distance from the surface of
the water to the tip of the air outlet tube). Draw at least one conclusion from
the graph.
Conclusion: According to the graph above, we can conclude
that when X which is the distance from the surface of the water to the tip of the
air outlet tube increases, the average flow rate of the pump will increase also.
2. Plot tube length Y versus pump flowrate. (Y is the distance from the surface of the water to the tip of the U-shape tube that is submerged in water). Draw at least one conclusion from the graph.
Conclusion: According to the graph above, we can conclude that when Y which is the distance from the surface of the water to the tip of the U-shape tube increases, the average flowrate of pump will increase also.
3. Summarise the learning, observations and reflection in about 150 to 200 words.
Answer: As seen from our results, as both X
and Y increases, the average flowrate of water also increase. In experiment 1,
the increase of the flowrate is relatively gradual, whereas in experiment 2,
the increase of the flowrate is abrupt. In experiment 1, the variable that causes
X to change is the length of the tip of the tube from the opening of the U-tube
(a), causing a change to the height of the surface to the tip of the tube. As
for experiment 2, the variable that causes Y to change is the height of the
U-tube to the base of the container (b). The shorter the length between the
U-tube and the base of the tank, the higher the height between the surface of
water to the entrance of the U-tube and the flowrate is higher. A greater
distance between the opening of the flexible tube and the water level results
in a higher flowrate. This is noticeable in experiment 2 as there is a greater
difference in the length between the water level and the opening of the
flexible tube, Y compared to X in experiment 1.
4. Explain how you measure the volume of water accurately for the determination of the flowrate?
Answer: We
used a 300ml measuring cup with 50ml graduations and a 14ml small measuring cup
with 1ml graduations. When water started to flow from the U shaped tube, we
held the 300ml measuring cup below the opening of the U tube to ensure minimal
spillage, and if the level of water is below 50ml, we would use the 14ml measuring
cup to get the volume of water. Hence, it would be more accurate.
5.
How is the liquid flowrate of an air-lift pump
related to the air flowrate? Explain your reasoning.
Answer: The liquid flow rate is directly
proportional to the air flow rate. For a fixed time interval, a higher flow
rate of air would mean a larger volume of air is introduced to the tube that will
displace the water. Hence, since water is incompressible, when a larger volume
of air is introduced, a larger volume of water will also be displaced. Since
flowrate is volume per unit time, increasing the volume of water that is
displaced per unit time will result in a higher flowrate.
6.
Do you think
pump cavitation can happen in an air-lift pump? Explain.
Answer: No. Cavitation occurs in centrifugal pumps
that transport liquid. However, since the equipment being used to transfer
energy to the water is an air compressor, cavitation will not occur.
7.
What
is the flow regime that is most suitable for lifting water in an air-lift pump?
Explain.
Answer:
Turbulent
flow. In turbulent flow, water undergoes
irregular fluctuations and is being mixed. This makes it easier for the air from
the air lift pump to push the water up. As there are irregular fluctuations,
there are spaces for the compressed air to go in and mix with the water. Therefore,
the density of the air and water mixture will be lower than the density of
water only. Making it easier to rise up and make a loop out of the tube.
8.
What
is one assumption about the water level that has to be made? Explain.
Answer:
The water
level in the container did not change and is assumed to be “steady state”. The
U-tube is exposed to atmospheric pressure. This means that the water level in the
U-tube is the same as the water level in the container. The height of water in
the U-tube will affect how much water the pump will push out. Therefore, if the
water level in the tube is low, it will need more air to displace the same
amount of water out of the tube.
Appendix A
Table
1: Data collected from Experiment 1
|
a
(cm) |
X
(cm) |
Flowrate
(ml/s) |
Average
Flowrate (ml/s) |
||
|
Run
1 |
Run
2 |
Run
3 |
|||
|
2 |
13 |
6.33 |
6 |
5.83 |
6.05 |
|
4 |
11 |
4.17 |
4.5 |
3.83 |
4.17 |
|
6 |
9 |
2 |
2 |
2.17 |
2.06 |
|
8 |
7 |
1.07 |
1.3 |
1.17 |
1.18 |
|
10 |
5 |
0.4 |
0.5 |
0.4 |
0.43 |
Table
2: Data collected from Experiment 2
|
b
(cm) |
Y
(cm) |
Flowrate (ml/s) |
Average
Flowrate (ml/s) |
||
|
Run
1 |
Run
2 |
Run
3 |
|||
|
10 |
16.5 |
12 |
12.3 |
12 |
12.1 |
|
12 |
14.5 |
4.75 |
4.63 |
4.55 |
4.64 |
|
14 |
12.5 |
3.67 |
3.33 |
3.33 |
3.44 |
|
16 |
10.5 |
1.63 |
1.67 |
1.47 |
1.59 |
|
18 |
8.5 |
0.133 |
0.167 |
0.233 |
0.178 |
|
20 |
6.5 |
0 |
0 |
0 |
0 |






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